I can do the integral but what perplexes is me that it's solution is not in form of elementary functions!The differential equation of the form is given as d y d x = x y 2 Separating the variables, the given differential equation can be written as 1 y 2 d y = x d x ⇒ y – 2 d y = x d x – – – ( i) In the separating the variables technique we must keep the terms d y and d Explanation dy dx = x y ydy = xdx by exploiting the notation (separation) ∫ydy = ∫xdx further exploiting the notation 1 2 y2 = 1 2x2 d y2 = x2 2d x2 −y2 = − 2d x2 −y2 = c where c = −2d Depending on whether c is positive, negative or zero you get a hyperbola open to the x axis, open to the y =axis, or a pair of straight lines through the origin

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If x^(2)+xy+y^(2)=100 then find (dy)/(dx)
If x^(2)+xy+y^(2)=100 then find (dy)/(dx)- You have to use Implicit Differentiation, which is a special case of the chain rule, and the product rule dy dx = 2x x(1) dy dx y(1) Simplify dy dx = 2x x dy dx y Solve for dy dx dy dx −x dy dx = 2x y Factor out dy dx dy dx (1 − x) = 2x y Isolate dy dxThe differential equation of the form is given as d y d x = y x Separating the variables, the given differential equation can be written as 1 y d y = 1 x d x – – – ( i) With the separating the variable technique we must keep the terms d y and d x in the numerators with their respective functions Now integrating both sides of the




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X 2xyy 2=100Differentiating both sides wrt x we get,dxd (x 2xyy 2)= dxd (100)=0⇒2xy1x dxdy2y dxdy=0⇒2xy(x2y) dxdy=0∴dxdy=− x2y2xy edited by Beepin Find dy dx d y d x in of x2 xy y2 = 100 continuity 12 people found it helpful harivignesh2396 Answer This equation have two solutions 1 xy=c 2 y^2 x^2 = c Stepbystep explanation Advertisement
2 Answers { x 2 − y 2 = r 2 cos ( 2 θ) 2 x y = r 2 sin ( 2 θ) d x = cos ( θ) d r − r sin ( θ) d θ d y = sin ( θ) d r r cos ( θ) d θ When you report in the ODE, you can cancel the factor r 2, also collecting d r and d θ you'll find addition formulas for angle (Note that if z = x− c then the chain rules says that dzdy = dxdy ⋅ dzdx = dz/dxdxdy = dxdyDifferentiate with respect to x twice 4y 3 (dy/dx) = 9x 8 12y 2 (dy/dx) 2 4y 3 (d 2 y/dx 2) = 72x 7 Then you can solve for dy/dx in the first equation, substitute that into the second, and solve the second for d 2 y/dx 2
Click here 👆 to get an answer to your question ️ find dy/dx of x^2 xy y^2 = 100 by first principle of derivatives ??Compute answers using Wolfram's breakthrough technology & knowledgebase, relied on by millions of students & professionals For math, science, nutrition, historyCourse Title CHEMISTRY 101;




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This problem aims to familiarize us with higherorder differential equations The concept required to solve this problem is ordinary differential equations given at a specific point and product rule Here we are going to find the secondorder differential with the help of a reference point Now, an ordinary differential equation also known as ODE is an equation that implicatesIn this video I have shown how you can solve a complex differential equation by separating the variable and writing the general solution without any logarithWhy create a profile on Shaalaacom?




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if y = (1 sin2x/1 sin 2x) 1/2 show that dy/dx sec 2 (π/4 – x) = 0 donot go shortcut if y = log tan (∏/4 x/2) show that dy/dx = sec x donot go shortcut Queries asked on Sunday & after 7pm from Monday to Saturday will be answered after 12pm the next working dayStep 2 2 of 4 Substituting d x d t = 5 \dfrac {dx} {dt}=5 d t d x = 5, we get the rate of change in y y y as a function of x x x and y y y But x x x and y y y are related by the given equation x y = 100 xy=100 x y = 100 Eliminating y y y, thus expressing d y d t I would have written it a little differently since y^3= x^4, multiply both numerator and denominator of 4y/9x^2 by x^2 to get d^2y/dx^2= 4x^2y/9x^4= 4x^2y/9y^3= 4x^2/9y^2 d^2y/dx^2= (4x/9y) (y^2/x^3) d^2y/dx^2=4x/9y Click to expand But that last equation is certainly NOT true it is missing the "squares"




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Answer (1 of 7) y^2x^2\dfrac{dy}{dx}=xy\dfrac{dy}{dx} x\dfrac{dy}{dx}(xy)=y^2 \dfrac{dy}{dx}=\dfrac{y^2}{x(xy)} This is homogeneous differential equation Put y 355 0 I have done it this way i have put 1/y=t =>1/y^2dy=dt dt/dx xt =1 Integrating factor comes out to be e^ (x^2/2) So finally i have to integrate e^ (x^2/2) to get the solution!To find the derivative of function in the form y = x f ( x), you need to know that ( ln f ( x)) ′ = f ′ ( x) f ( x), so f ′ ( x) = f ( x) ( ln f ( x)) ′ Then differentiate both sides and think that y = f ( x) and x is the independent variable, ie ( x y) ′ ( y x) ′ = 0




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Q Show that y=xex satisfies the equation dy/dx y=ex A We find dy/dx using product rule Q Given the initial condition y(0) = 1, find the particular solution of the equationY = x 4 c 4 x 2 Explanation of the correct option Compute the required value Given x d y d x 2 y = x 2 ⇒ d y d x y 2 x = x Compare the equation with standard LDE d y d x P y = Q P = 2 x and Q = x Now, I F = e ∫ P dx = e ∫ 2 x dx ∫ 1 x dx = ln x = e 2 ln x = e ln x 2 = x 2 Since the solution of LDE is given by y Answer32Stepbystep explanationx² xy = Take the derivative with respect to time2x dx/dt x dy/dt y dx/dt = (2x y) dx/dt x dy/dt = Given x =




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Let us find the derivative on both sides with respect to x On differentiating with respect to x, we get d/dx ( x 2 x y y 2) = d/dx (100) ⇒ d/dx (x 2) d/dx (xy) d/dx (y 2) = 0 Since derivative of constant function is zero ⇒ 2x y d/dx (x) x dy/dx 2y dy/dx = 0 ⇒ 2x y (x 2y) dy/dx = 0 Therefore, dy/dx = (2x y) / (x 2y) I'm using y'=(dy/dx) I found the derivative of the above problem First I used the quotient rule 6x=(2y)(y')(2y)(y')/(2y)^2 6x=(2y'yy'2y'yy') 6x=2yy'/(2yy')^2 After this, I got into a jumbled mess, I wasn't sure if I had to add y' to the bottom of the quotient rule I checked the answer in the back of the book and it was y'=3x(2yFind Dx/Dy for X2 Xy Y2 = 100 CBSE CBSE (Commerce) Class 12 Question Papers 1799 Textbook Solutions MCQ Online Tests 29 The given relationship is x 2 xy y2 = 100 Differentiating this relationship with respect to x, we obtain Concept Derivatives of




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1 Inform you about time table of exam 2 Inform you about new question papers 3 New video tutorials informationConsider the ellipse x^2 xy y^2 = 1 a Find an equation for dy/dx in terms of x and y b Find all points where the tangent line is horizontal c Find all points where the tangent line is parallel to the line y = x Question Consider the ellipse x^2 xy y^2 = 1 a Find an equation for dy/dx in terms of x and y b Find all pointsGive the BNAT exam to get a 100% scholarship for BYJUS courses




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Answer (1 of 4) Let's do this in 3 ways — Way 1 Implicit Differentiation \displaystyle x^2xy=5 Differentiate wrt x \displaystyle 2xyx \frac{dy}{dx}=0 Do algebra \displaystyle 2xy=x \frac{dy}{dx} Divide by x \displaystyle \frac{dy}{dx}=2\frac{y}{x} — Way 2 Implicit DiffereStepbystep explanation Sol Given equation is 2zy my2 = 16 0 Differentiating both sides of @ wY to x, we get 72 dy 2x da ( 2 2 ) ax zy dy 2 ( x ) = 0 ( x 2 2 xy ) dy 2 2 7 4 2 x 1 = 0 = ( 2x 4 42 ) ( 2 2 2 x y ) dy da y ( y 2 2 ) 2 ( 2 2y ) The tangent line will be horizontal if dy 2 0 7 (4 2x ) = 0 21 ( 2 You have \displaystyle lny= x^2 C ln∣y∣ = x2 C and found that C= ln (2) So you have \displaystyle lny= x^2 ln (2) ln∣y∣ = x2 ln(2) and, taking the exponential on each side, \displaystyle y= e^ {x^2 ln (2)}= e^ {x^2}e^ {ln (2)}= 2e^ {x^2} ∣y∣ = ex2ln(2) = ex2eln(2) = 2ex2 Also, note that you do not need the absolute




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Use implicit differentiation to find dy dx x xy cot 2 dy dx Answer y sin 2 xy x Use implicit differentiation to find dy dx x xy cot 2 School Redondo Union High;Let's simplify it First dy/dx = (y/x 1)/ (y/x 1) Taking y = vx dy/dx = v xdv/dx Therefore, dx/x = (v 1)dv / (v^2 1) Integrating we get log (1/x) logc = arctan (y/x) 1/2 log How to show that dxdy = d(x−c)dy?X2 xy = 10 x 2 x y = 10 Differentiate both sides of the equation d dx (x2 xy) = d dx(10) d d x ( x 2 x y) = d d x ( 10) Differentiate the left side of the equation Tap for more steps xy' 2xy x y ′ 2 x y Since 10 10 is constant with respect to x x,




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Solve your math problems using our free math solver with stepbystep solutions Our math solver supports basic math, prealgebra, algebra, trigonometry, calculus and moreGiven x 2xyy 2=100Differentiating both sides, we get2xxyy2yy=0(2xy)(x2y)y=0y=− x2yx2yType Notes Uploaded By oasysokubo Pages 25 Ratings 100% (2)




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Find dy/dx by implicit differentiation x^2 y^2 = 100 x^3 y^3 = 3xy^2 x^2y 3xy^3 x = 3 x^3y^2 5x^2y x = 1 1/squareroot x 1/squareroot y = 1 x^2 = x y/x y sin (x^2 y^2) = x cos (xy^2) = y Find d^2y/dx^2 by implicit differentiation 2x^2 3y^2 = 4 x^3 y^3 = 1 x^3y^3 4 = 0Calculus Find dy/dx x^2y^2=100 x2 y2 = 100 x 2 y 2 = 100 Differentiate both sides of the equation d dx (x2 y2) = d dx (100) d d x ( x 2 y 2) = d d x ( 100) Differentiate the left side of the equation Tap for more steps 2y d dx y2x 2 y d d x y 2 x Since 100 100 is constant with respect to x x, the derivative of 100 100Thumb_up 100% Hi, I am looking at an example on homogeneous differential equations I do not understand one part of this example The example is solving the differential equation dy/dx = (x^2 y^2)/ (xy) I follow all of its steps until this step (v^2)/2 = ln (x) C However, in the next step the example states that C = ln (k), and it follows to write the top equatoin as (v^2)/2 = ln (x) ln (k)




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